Bob Arum, the veteran boxing promoter, has indicated his willingness to arrange a fight between WBC lightweight champion Shakur Stevenson and William Zepeda. The potential bout is slated for July 6th at the Prudential Center in Newark, New Jersey. This announcement comes in the wake of Stevenson's expressed interest in facing Zepeda, following the latter's impressive fourth-round knockout victory over Maxi Hughes. The fight, if realized, would mark Stevenson’s next engagement in the ring and is poised to draw significant attention.
Watch Zepeda vs. Hughes highlights: Watch
Arum’s openness to the matchup hinges on discussions with Zepeda’s promoter, Oscar De La Hoya, emphasizing the timing and logistical aspects of the fight. This proposal comes despite Zepeda’s recent rigorous training schedule, which might complicate immediate preparations for a July showdown. Arum’s strategy appears to navigate the contractual landscape with Stevenson, who is approaching the end of his tenure with Top Rank. A fight against Zepeda could serve multiple strategic purposes for Arum, including a high-profile event that could impact Stevenson's market value should he depart from Top Rank.
The potential Stevenson vs. Zepeda fight embodies a high-stakes confrontation that could reshape the lightweight division. Both fighters bring undefeated records and a history of compelling performances, promising a compelling clash for boxing enthusiasts. As negotiations unfold, the boxing community eagerly anticipates official confirmation of this summer showdown in Newark.
Image Credit: Sky Sports